If O is the centre of the circle, find the value of x:
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Answer:
) ∠ACB=∠ADB (Angles in the same segment of a circle)
But ∠ADB=x
o
⇒∠ABC=x
o
Now in ΔABC
∠CAB+∠ABC+∠ACB=180
o
⇒40
o
+90
0
+x
o
=180
o
(AC is the diameter)
⇒130
o
+x
o
=180
o
⇒x
o
=180
0
−130
o
=50
o
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