if O is the centre of the circle ,PQ is chord & the tangent PR at P makes an angle 50° with PQ find angle POQ
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Angle POQ= 100 DEGREE
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Vishnu04:
it is some what not clear can you please re upload it with clear picture
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Given : O is the center of the circle ,PQ is chord & the tangent PR at P makes an angle 50° with PQ
To Find : ∠POQ
Solution:
PR is tangent
Hence ∠OPR = 90°
tangent PR at P makes an angle 50° with PQ
=> ∠QPR = 50°
∠OPR = ∠OPQ + ∠QPR
=> 90° = ∠OPQ + 50°
=> ∠OPQ = 40°
∠OQP = ∠OPQ ∵ OP = OQ ( Radius)
=> ∠OQP = 40°
in ΔOPQ sum of angles of triangle = 180°
=> ∠OQP + ∠OPQ + ∠POQ = 180°
=> 40° + 40° + ∠POQ = 180°
=> ∠POQ = 100°
∠POQ = 100°
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