Question

If o<A, B < 90°, cos A = 5/13and sin B =4/5
then find i) sin (A + B) ii) sin (A -b)​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Cos A = 5/13 and sin B = 4/5

Then,

sin A = √1 - cos²A

        = √1 - (5/13)²

        = √1 - 25/169

        = √144/169

        = 12/13

Also,

Cos B = √1 - sin²B

          = √1 - 16/25

         = 3/5

Now,

(i) sin(A + B)

⇒ sin A * cos B + cos A * sin B

⇒ 12/13 * 3/5 + 5/13 * 4/5

⇒ 56/65

(ii) sin(A - B)

⇒ sin A cos B - cos A sin B

⇒ 12/13 * 3/5 - 5/13 * 4/5

⇒ 16/65

Hope it helps!Brainliest it Sister!