Question

If OA = i + j + k, AB = 3i - 2j +k, BC = i + 2j - 2k and CD = 2i + j + 3k, then find the vector OD.

Answer 1

Answer:THERE FORE VECTOR OD 7I+2J+3K

Step-by-step explanation:p { margin-bottom: 0.25cm; line-height: 120%; }

GIVEN VECTORS OA=I+J+K;AB=3I-2J+K;BC=I+2J-2K AND CD=2I+J+3K

WE KNOW THAT VECTOR AB =OB-OA

3I-2J+K= OB-( I+J+K)

OB=4I-J+2K

SIMILARLY BC =OC-OB

I+2J-2K=OC-(4I-J+2K)

OC=5I+J

CD=OD-OC

2I+J+3K = OD -(5I+J)

OD=7I+2J+3K

THERE FORE VECTOR OD 7I+2J+3K