Question

If object moves with velocity of 5m/s,10m/s,15m/s in every 5 seconds then find average velocity?
Explain briefly please!!
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Answer 1

Answer:

• 10m/s is the required average velocity .

Explanation:

According to the Question

It is given that object change its velocity every 5 seconds .

• v₁ = 5m/s
• v₂ = 10m/s
• v₃ = 15m/s
• Time taken in every case ,t = 5 s

Now, we know that average velocity is calculated by the total displacement divided by total time taken.

Displacement for First Case

→ S = 5×5 = 25m

Displacement for second case

→ S = 10×5 = 50m

Displacement for third case

→ S = 15×5 = 75 m

Now calculating average velocity

• Average Velocity = Total Displacement/Total Time

by putting the value we get

➻ Average Velocity = S₁ + S₂ + S₃ /t

➻ Average Velocity = 25+50+75/15

➻ Average Velocity = 150/15

➻ Average Velocity = 10m/s

• Hence, the average velocity of the object is 10m/s.

Answer 2

Given :-

• If object moves with velocity of 5m/s, 10m/s, 15m/s in every 5 seconds then find average velocity?

To Find :-

• Average velocity?

Solution :-

We have,

• v₁ = 5m/s
• v₂ = 10m/s
• v₃ = 15m/s
• Time taken in each case = 5s

Finding distance travelled in each case by using formula of distance i.e, s = v × t where s denotes distance, v denotes velocity and t denotes time.

• Case (1)

➡ s₁ = v₁ × t

➡ s₁ = 5 × 5

➡ s₁ = 25m

• Case (2)

➡ s₂ = v₂ × t

➡ s₂ = 10 × 5

➡ s₂ = 50m

• Case (3)

➡ s₃ = v₃ × t

➡ s₃ = 15 × 5

➡ s₃ = 75m

Now, let's calculate its average velocity.

We know that,

$\hookrightarrow\:\boxed{\sf{Average\:velocity} = \dfrac{Total\:distance}{Total\:time}}$

As time is same in each case so total time will be 3 × 5 i.e, 15s.

$\tt \longmapsto\: Average\:velocity = \dfrac{s_{1} + s_{2} + s_{3}}{15}$

$\tt \longmapsto\: Average\:velocity = \dfrac{25 + 50 + 75}{15}$

$\tt \longmapsto\: Average\:velocity = \dfrac{75 + 75}{15}$

$\tt \longmapsto\: Average\:velocity = {\cancel{\dfrac{150}{15}}}$

$\purple{\longmapsto}\:{\underline{\boxed{\bf{\blue{Average\:\pink{velocity} \green{=} \red{10m/s}}}}}}$

Learn More :-

Question:

• Abdul, while driving to school, computes the average speed for his trip to be 20 km hl. On his return trip along the same route, there is less traffic and the average speed is 30 km h-!. What is the average speed for Abdul's trip?

Answer:

• brainly.in/question/43685797

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