if omega is a complex cube root of unity, show that (2-omega)(2-omega²)=7
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Step-by-step explanation:
(2-w)(2-w²)=4-2w²-2w+w³
now we know one thing that 1+w+w²=0
now what you do multiply both side with 2
so that's equal to 2+2w+2w²=0, 2= -2w-2w²
w³=1
so from beginning
4+2+1=7
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