Question

If on heating a liquid through 80 degree celsius ,the mass expelled is 1/100 of mass still remaining the coefficient of apparent expansion of the liquid is

Answer 1

Answer:

$1.25*10^{-4}/^0C$

Step-by-step explanation:

The givens are: $T=80^0C$ and $mass\:expelled=\frac{mass\:remaining}{100}$.

It is required to find the coefficient of apparent expansion of the liquid ($\gamma_{app}$).

The definition of $\gamma_{app}$ is the apparent increase in the volume of liquid per unit original volume per degree rise in temperature.

It is calculated using the following formula:

$\gamma_{app}=\frac{mass\:expelled}{mass\:remained*ΔT}=\frac{mass\:remained/100}{mass\:remained*80}\\ =\frac{1}{8000}\\=1.25*10^{-4}/^0C$

Answer 2

Answer:

1.25×10^-4/℃

Step-by-step explanation: