Question

If on Increasing the speed of a vehicle by 2 m/s, the kinectic energy gets double, then what would be the average resistive force.​

Answer 1

Answer:

2(√2+1)

Explanation:

Let original speed of the vehicle is v

Let original speed of the vehicle is v2

Let original speed of the vehicle is v21

Let original speed of the vehicle is v21

Let original speed of the vehicle is v21 m(v+2)

Let original speed of the vehicle is v21 m(v+2) 2

Let original speed of the vehicle is v21 m(v+2) 2 =2(

Let original speed of the vehicle is v21 m(v+2) 2 =2( 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2=

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒(

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v=

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −1

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 ×

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2 +1

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2 +12

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2 +12

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2 +12 +1

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2 +12 +1

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2 +12 +1 =2(

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2 +12 +1 =2( 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2 +12 +1 =2( 2

Let original speed of the vehicle is v21 m(v+2) 2 =2( 21 mv 2 )v+2= 2 v⇒( 2 −1)v=2⇒v= 2 −12 × 2 +12 +1 =2( 2 +1)

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