If on the x-axis electric potential decreases uniformly from 60 volt 220 volt between x is equals to minus 2 m 2 x is equals to + 2 me then the magnitude of electric field at the origin is
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ELECTRIC FIELD CAN BE DEFINED AS negative gradient,
E=E=-(v2-v1)/d
E=-220+60/4
the value of voltage 2 =v2 is 220 v
and the value of voltage 1 is v1= 60 volt
E=40 V/m
so that electric potential decreases uniformly so that the path will be uniform..
the field is same at x=0..
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