Question

If one angle of a iigm is 24 less than twice the smallest angle, find all the angles of parallelogram

Answer 1

let ABCD be a parallelogram in which angle A is smaller and = X so angle B = 2x - 24
now angle A + angle B = 180
X + 2x - 24 = 180
3x = 204
x = 68
so 2x - 24 = 136 - 24 = 112
hence, angle A = angle C = 68 and angle B = angle D = 112