if one angle of a parallelogram is 24 less than twice the smallest angle find all the angles of the parallelogram
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let the smallest angle be x
second angle =2x-24
AB parallel CD
angleA +anglB = 180
x+2x-24= 180
x = 52
x=68
angleA=angleC=X
=68
angleB=2x-24
=136-24
=112
angleC=112
second angle =2x-24
AB parallel CD
angleA +anglB = 180
x+2x-24= 180
x = 52
x=68
angleA=angleC=X
=68
angleB=2x-24
=136-24
=112
angleC=112
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laxmi4973:
thanks
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