Question

If one angle of a parallelogram is 24° less than twice the smallest angle find all angels of tge parallelogram

Answer 1

Solution :

Let smallest angle = x ,

Second angle = ( 2x - 24° )

Sum of adjacent angles in a

parallelogram = 180°

=> x + 2x - 24 = 180°

=> 3x = 180 + 24

=> 3x = 204

=> x = 204/3

=> x = 68°

Therefore ,

one angle = x = 68°

second angle = ( 2x - 24 )

= 2 × 68 - 24

= 136 - 24

= 112

Therefore ,

All 4 Angeles in a parallelogram are

68° , 112° , 68° , 112°

[ Since , Opposite angles are equal

in a parallelogram ]

•••