if one angle of a triangle is 80° and the other two angles are in the ratio 3 is to 7
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other angles are 30 and 70
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sum of all angles in triangle is 180
let the another two angles be 3x,7x
so first we have to sum all angles
80+3x+7x=180
80+10x=180
10x=180-80
10x=100
x=100÷10=10
therefore another two angles are 30,70
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let the another two angles be 3x,7x
so first we have to sum all angles
80+3x+7x=180
80+10x=180
10x=180-80
10x=100
x=100÷10=10
therefore another two angles are 30,70
pls follow me
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