If one angle of quadrilateral 102° and the other three angles are equal find all the angles?
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We know that sum of all four angles of a quadrilateral is 360°.
Since, 3 angles are equal. Let x.
So, x + x + x + 102 ° = 360°
3x = 360 ° - 102 °
x = 258 / 3
x = 86°
Hence, all the other 3 angles are 86° each.
Since, 3 angles are equal. Let x.
So, x + x + x + 102 ° = 360°
3x = 360 ° - 102 °
x = 258 / 3
x = 86°
Hence, all the other 3 angles are 86° each.
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