Question

if one angle of triangle is 2/3 of rights angle.if the greater of the other two exceeds the smaller angle by 18.find the all angles in radian

Answer 1

So thus the angles would be 90 and then 2/3 *90 = 60
Then by asp
90 + 60 + x = 180
X = 180 -150
X = 30

Answer 2

2/3 * 90 = 60

if one angle exceeds other by 18, then by ASP

angle 1 + angle 2 + angle 3 = 180
60 + x + x+18 = 180
2x = 180-78
x = 51

hence, the last angle is x+18 = 51+18 = 69

therefore, all angles are 60,51 and 69