Question

if one end of diameter of a circle is (-2,3) and centre of circle is (0,3) then find the other end of the diameter?​

Answer 1

Answer:

(2, 3)

Step-by-step explanation:

Let the other end be(x, y)

centre is the mid point of two ends of diameter.

So, we know that midpoint for (x1, y1),(x2, y2) is((x1+x2) /2,(y1+y2) /2)

so,

(0,3)=((-2+x) /2,(3+y) /2)

0=(-2+x)/2;3=(3+y)/2

x-2=0;y+3=6

x=2;y=6-3=3

x=2,y=3

Other end of diameter is (2,3)

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Answer 2

Answer:

(2,3)

Step-by-step explanation:

Since y axis is constant at both either side and centre of diameter so, the diameter is taken only from x axis.

NOW, centre of the circle is 0 point of X axis, so the length on either side should be equal .

Since one end of diameter is as (-2,3) i.e 2 units at negative side

So, other end would be 2 units at positive side of X axis.

Thus the required point is (2,3)