Question

if one end of the diameter of a circle as origin is (-2, 10), then the length of diameter of the circle is?

Answer 1

Step-by-step explanation:

Let A= (-2,10) B=(0,0)

$d = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$

=

$\sqrt{( - 2 - 0) {}^{2} + (10 - 0) {}^{2} }$

=

$\sqrt{4 + 100}$

=

$10 \sqrt{4}$

HOPE THIS HELPS........