Question

if one is a zero of the polynomial ax²–3(a-1)x-1 find the value of a

Answer 1

Here your answer goes

Given ,

p(x) $ax^2 - 3 ( a - 1) x - 1$

Put 1 in place of x

p(1) = $0 = a1^2 - 3 (a - 1) 1 -1$

a - 3a + 3 - 1 = 0

2 = 2a

a = 1

↓↓

Be Brainly

Together we go far →→

Answer 2

ANSWEE:-
The value of a is 1.