If one joule of energy is required to stretch a spring through 20cm, the force constant of that spring is
Answers
Answered by
28
Answer:
Explanation:
given, streching length(x)=20cm=0.2m and energy(e)=1J
since, e=kx^2/2
1=k(o.2)^2/2
0.04k=2
k=50 N/m
Answered by
17
Given:
Energy E = 1J
length x = 20cm
To Find:
Force constant of spring k
Solution:
x = 20cm = 20/100 = 0.2 m
We Know, Energy stored in the spring when it is stretched up to length "x" is given by
E = k
k = 2E /
k = 2 * 1 /
k = 2/
k = 2/0.04
k = 50 N/m
So, the force constant of that spring is 50 N/m.
Similar questions