If one leg of a right triangle is 8 inches long, and the other leg is 12 inches long, how many inches long is the triangle's hypotenuse?
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Answer:. Let H = Hypotenuse; P = 1st leg and B = 2nd leg. Then, by Pythagoras theorem,
H^2 = P^2 + B^2
= (8)^2 + (12)^2
= 64 + 144
= 208
H = √208 = 4√13
H = 4√13 cm.
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