Question

If one litre of n2 at 27 degree celsius and 760 contains n molecules, 4 litres of o2 under the same conditions of temperature and pressure contain

Answer 1

Answer:

Explanation:

From ideal gas eqn. PV = nRT,

moles for O2 => PV/RT => 1*1/RT

no. of molecules,

N = Na/RT............(1)

SIMILARLY FOR SO2,

moles of SO2 => PV/RT => 1*2/RT

no. of molecules,

M = 2Na/RT........(2)

divide both the eqns. we get,

N/M = ½

M = 2N