Question

If one member of a pythagorean triplet is 10, then the other two members are

Answer 1

take the square of 10 (10^2=100)

divide it by 2 (100/2=50)

i)add 2 to 50(50+2=52) ii)subtract 2 by 50(50–2=48)

divide them by 2;

i)52/2=26 ii)48/2=24

10,24,26 are the triple (10^2+24^2=26^2)

and because 3,4,5 are a triple their double must also be so 6,8,10 are also a triple(6^2+8^2=10^2)

Answer 2

Answer:

The other two members are 24 and 26.

Step-by-step explanation:

Pythagorean triples are $a^2+b^2 = c^2$where a, b, and c are the three positive integers.

We know that $2m$,  $m^2+1$, $m^2-1$ form a Pythagorean triplet for any number m > 1.

Let us assume 2m=10

                        $m=\frac{10}{2}$

                        m = 5

Now $m ^2 +1 = 5 ^2 +1$

                      =25+1

                       =26

and

$m ^2 -1 = 5 ^2 -1$

           = 25-1

           =24

Hence, the other two members are 24 and 26.