Question

If one member of a pythagorean triplet is 2m, then the other two members are?

Answer 1

Answer:

2m is the smallest member of Pythagorean triplet

so for 2m

it will be

$(2m) {}^{2} + (m {}^{2} - 1) {}^{2 } = (m {}^{2} + 1) {}^{2}$

hope it may help u

Answer 2

We know that, for any natural number m greater than 1, (2m, (m²-1), (m²+1)) is a pythagorean triplets.

So,

One number is 2m

Then other numbers are (m²+1) and (m²-1)

Let us take an example to understand.

One number be 4

The the pythagorean triplet,

2m = 4

$\implies$m= 2

m²+1 = 2²+1 = 4+1 = 5

and

m²-1 = 2²-1 = 4-1 = 3

Now,

3² + 4² = 5²

9 + 16 = 25

So,

(3,4,5) are pythogorean triplets.