If one mole of ethyl alcohol requires 3 mole of oxygen then how much oxygen is requires for 56gm of ethane
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Answer:
the answer is 3 moles
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Answer:
1 mole ethyl alcohol, CH3CH2OH has molar mass of 46 g
56g x 1 mol/46 g = 1.217 moles CH3CH2OH
moles oxygen required for 56 g = 3 mol Oxy/ mole CH3CH2OH x 1.217 moles CH3CH2OH = 3.65 moles oxygen.
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