Question

if one mole of Zn is added to 1L of HCL what volume of H2 gas at STP would be given off...?​

Answer 1

Answer:

equivalent concept is easy  follow it blindly

Explanation:

i will say simple trick

weight of zn = 65.38

moles=1/22.4

=0.044

weight = 0.088

write reaction between zn and hcl

zn+2hcl = h2+zncl2

find mole/coefficient of reactants

for zn it is 1 and for hcl it is 0.022

so hcl will be limiting reagent

h2 formed will be stichiometric coefficient of h2 * limiiting ratio

0.022 mole =h2 formed

we know that 1 mole has 22.4 lt

volume = 0.4928 lt

alter method:

equivalent of h2 formed = equivalent of limiting reagent

equivalent of zn = 2

equivalent of hcl = 0.044

equivalent of h2 formed = 0.044

moles*2=0.044

moles=0.022

w=0.044 gm

vol = 0.4928 lt