if one newton force is applied on a wire having a cross section area 1 square metre then stress produced in wire is
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Work done =21×stress×strain×volume
=21×Y×(strain)2×volume
=21×Y×(LI)2×AL
=21×Y×L2I2×AL
=2LYI2A
=2LYI2A
Hence, the answer is 2LYI2A.
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