if one number is 5 more than the other and their sum is 29, find the smaller number
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zeborg:
Lol, mistake in calculation. Subtract the 5 on rhs from 29. I'm sorry for that.
Answered by
7
let 1st no. be x then 2nd no.= x+5
A/q x+x+5=29
2x+5= 29
2x= 24
x=12
smaller no. = 12
A/q x+x+5=29
2x+5= 29
2x= 24
x=12
smaller no. = 12
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