If one number is divide by 345,the remainder is 35.If the same number is divided by 15.What is the remainder
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Solution 1:
Let N=345×q+35
=15(23q)+15×2+5.
So the remainder will be 5
Solution 2:
Let that one number is x
then x=345×a+35
now 345÷15=23 , ie 23×15=345
So, x=15×23×a+35 =15×23×a+15×2+5
=15(23×a+2)+5
Then x will be divided by 15
The remainder will be 5
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