Question

when a 12 gold battery is connected across unknown resistors the current of 2.5 milli A flows.Find the value of resistance of resistor ...... Explain it...

Answer 1

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According to Ohm’s law,

V = IR

=v/I

Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore,

=12/ 0.0025 = 4800 Ω = 4.8 kΩ

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Answer 2

Answer:

R=V/I

R=12/2.5

=4.8 ohm