If one number is divided by 345 the remainder is 35 if the same number is divided by 15 what is the rem
ainder
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Answered by
0
let the number be "x"
the number "x" is divided by "345" and we get remainder as "35" , hence we can write
x = 345 y + 35 where y = integer
rearranging the expression so that we have "15" in multiple
x = (23 x 15) y + 30 + 5
x = (23 x 15) y + (15 x 2) + 5
x = 15 (23 y + 2) + 5
hence dividing the number by "15" , we get remainder "5"
Answered by
1
Solution 1:
Let N=345×q+35
=15(23q)+15×2+5.
So the remainder will be 5
Solution 2:
Let that one number is x
then x=345×a+35
now 345÷15=23 , ie 23×15=345
So, x=15×23×a+35 =15×23×a+15×2+5
=15(23×a+2)+5
Then x will be divided by 15
The remainder will be 5
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