Question

If one of a parallelogram is 24degree less than twice the smallest angle then the largest angle of the parallelogram is?


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Answer 1

Answer:

According to the problem, we are given that one of the angles of parallelogram is 24 degree less than the twice of the smallest angle. Let the smallest Angle be x. For a parallelogram the smallest and the largest angles are adjacent angles. Now according to the question the largest angle will be 2 x - 24 in degrees.

Answer 2

Answer:

$\bf{\underline{Given:-}}$

If one angle of parallelogram is 24° less than twice the smaller angle.

$\bf{\underline{To find :-}}$

The largest angle of parallelogram

$\bf{\underline{Solution :-}}$

Let the smallest angle be x

and largest angle be 2x - 24°

we know that,sum of adjacent angle of a parallelogram is 180°.

Now,

According to the above values,

x + 2x - 24° = 180°

⤇ 3x - 24° = 180°

⤇ 3x = 180° + 24°

⤇ 3x = 204°

⤇ x = 204/3

⤇ x = 68°

Then,

⤇ 180° - 68°

⤇ 112°

Hence,the largest angle of the Parallelogram will be 112°.