If one of the base angle of an isoceles triangle is 49 degree then find the measure of it's vertex angle
Answers
Answered by
3
Answer:
82
Step-by-step explanation:
Sum of all angles in a triangle=180
Thus,
49+49+x=180
98+x=180
x=180-98
x=82
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Answered by
2
Answer:
∠A = 82°
Step-by-step explanation:
Let the triangle be ΔABC, Where 'B' & 'C' are the base angles and 'A' is the vertex angle.
Given: AB=AC, ∠B= 49°
To Find: ∠A= ?
Since, we know that the base angles of an isosceles triangle are equal.
∠C=∠B
∴ ∠C= 49° ( Substitute from given ) ----> (1)
∠A + ∠B + ∠C = 180° ( Angle Sum Property of Triangles )
∠A + 49 + 49 = 180 ( Substitute from (1) and given )
∠A + 98 = 180
∠A = 180 - 98
∴ ∠A = 82°
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