Math, asked by aditikatiyar75, 1 month ago

If one of the base angle of an isoceles triangle is 49 degree then find the measure of it's vertex angle​

Answers

Answered by pampa251281
3

Answer:

82

Step-by-step explanation:

Sum of all angles in a triangle=180

Thus,

49+49+x=180

98+x=180

x=180-98

x=82

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Answered by FantasyWorld2
2

Answer:

∠A = 82°

Step-by-step explanation:

Let the triangle be ΔABC, Where 'B' & 'C' are the base angles and 'A' is the vertex angle.

Given: AB=AC, ∠B= 49°

To Find: ∠A= ?

Since, we know that the base angles of an isosceles triangle are equal.

∠C=∠B

∴ ∠C= 49°  ( Substitute from given ) ----> (1)

∠A + ∠B + ∠C = 180° ( Angle Sum Property of Triangles )

∠A + 49 + 49 = 180  ( Substitute from (1) and given )

∠A + 98 = 180

∠A = 180 - 98

∴ ∠A = 82°

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