Question

if one of the cubic polynomial x³+px²+qx+r is -1, then the product of the other two zeroes is​

Answer 1

Answer:

(c) q- p + 1 is the answer.

Step-by-step explaination :

Let p(x) = x³ + px² + qx + r

p(-1) = 0

(-1)³+p(-1)²+q(-1) + r = 0

-1+ p -q + r = 0

r = q- p + 1

$let \: \: zeroes \: \: be \: \: \alpha , \beta \: \: and \: \: \gamma . \\ \alpha \beta \gamma = \frac{ - d}{a} \\ \alpha \beta ( - 1) = \frac{ - r}{1} \\ - \alpha \beta = - r \\ \alpha \beta = r \\ \alpha \beta = q - p + 1$

Answer 2

Answer:

q-p+1 answer

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