If one of the equal legs of an isosceles right-angled triangle is increased by 6 cm and the other leg is
increased by 4 cm. then change in area of the triangle is 24 sq. cm. Find the length of the leg of the
original triangle
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Answer:
2.4cm
Step-by-step explanation:
Let x be the leg
Then area of triangle=x²/2
Now the area=(x+4)(x+6)/2
As per question (x+4)(x+6)/2-x²/2=24
⇒ x²+10x+24-x²=48
⇒ 10x=24
⇒ x=2.4
Original length of leg is 2.4 cm
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