If one of the interior angles of a regular polygon is equal to 5/6 times of one of the interior angles of a regular pentagon, then the number of sides of the polygon is
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Interior angles of a pentagon is 180(4)/5 = 132
let the number of sides of a polygon is n
180(n-2)/n = 5/6(132)
simplify it the value of n will be equal to 5
let the number of sides of a polygon is n
180(n-2)/n = 5/6(132)
simplify it the value of n will be equal to 5
cvrohit:
he gave n=4
In the key
I think you did a worng
n will be equal to 4 when the figure is a regular hexagon but in the question you have send it as regular pentagon
Yes
if it was a hexagon then 180 (4)/5 = 120 and 180 (n-2)/n = 5/6(120) , solving this u will get answer as 4
For a regular pentagon
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Answer:
Give one of the interior angles of a regular polygon is equal to 5 by 6 times of one of the interior angles of a regular pentagon, then the number of sides of the polygon is
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