Math, asked by cvrohit, 1 year ago

If one of the interior angles of a regular polygon is equal to 5/6 times of one of the interior angles of a regular pentagon, then the number of sides of the polygon is

Answers

Answered by Dada1235

Interior angles of a pentagon is 180(4)/5 = 132

let the number of sides of a polygon is n

180(n-2)/n = 5/6(132)

simplify it the value of n will be equal to 5

cvrohit: he gave n=4

cvrohit: In the key

cvrohit: I think you did a worng

Dada1235: n will be equal to 4 when the figure is a regular hexagon but in the question you have send it as regular pentagon

cvrohit: Yes

Dada1235: if it was a hexagon then 180 (4)/5 = 120 and 180 (n-2)/n = 5/6(120) , solving this u will get answer as 4

cvrohit: For a regular pentagon

Answered by Keerthi00

Answer:

Give one of the interior angles of a regular polygon is equal to 5 by 6 times of one of the interior angles of a regular pentagon, then the number of sides of the polygon is

Step-by-step explanation:

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