Question

If one of the quadratic polynomial (k-2)x2 -2x-(k+5) is 4 , then find the value of k

Answer 1

Heya !!!



P(X) = ( K-2)X² -2X - ( K+5)



Given that 4 is one zero of the given polynomial.




P(4) = ( K-2) × (4)² - 2 × 4 - ( K+5)




=> ( K-2) × 16 - 8 - K -5 = 0



=> 16K - 32 - 8 - K -5 = 0


=> 15K - 45 = 0



=> 15K = 45


=> K = 45/15



=> K = 3.




HOPE IT WILL HELP YOU..... :-)

Answer 2

          Given that, one root = 4 

           Then, x = 4 

--------------------------------

(k - 2)x² - 2x - (k + 5) = 0 

(k - 2)(4)²  - 2(4)  - k - 5 = 0 

(k -2)(16) - 8 - k - 5 = 0 

16k - 32 - 8 - k - 5 = 0 

15k - 32 - 8 - 5 = 0 

15k  - 45 =  0

15k = 45 


k = 45/15 

k = 3 



i hope this will help you

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