Question

If one of the quadratic polynomial (k square+k) x square+68x+6k is reciprocal of the other .Find the value of k

Answer 1

Answer:

5

Step-by-step explanation:

(k² + k)x² + 68x + 6k

We know that ;

Product of zeroes = c /a

Let one zero be α and other be 1/α.

⇒ α * 1/ α = 6k / k² + k

⇒ 1 = 6k / k² + k

⇒ k² + k = 6k

⇒ k² + k - 6k = 0

⇒ k² - 5k = 0

⇒ k ( k - 5 ) = 0

⇒ k - 5 = 0

⇒ k = 5

Hence, the answer is 5.