If the pair of linear equations ax+2y=7 and 2x+3y=8 has a unique solution, then a ≠ ......,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) 3/4
(b) -3/4
(c) 4/3
(d) -4/3
Answers
Answered by
17
(c)4/3 is the correct answer.
Answered by
29
Option ( c ) is correct.
Explanation :
Compare given pair of linear
we equations
ax + 2y - 7 = 0 ---( 1 )
2x + 3y - 8 = 0 ----( 2 ) with
a1x + b1y + c1 = 0 and
a2x + b2y + c2 = 0
a1 = a , b1 = 2 , c1 = -7 ,
a2 = 2 , b2 = 3 , c3 = -8,
a1/a2 ≠ b1/b2
[ Given unique solution ]
=> a/2 ≠ 2/3
=> a ≠ 4/3
•••••
Explanation :
Compare given pair of linear
we equations
ax + 2y - 7 = 0 ---( 1 )
2x + 3y - 8 = 0 ----( 2 ) with
a1x + b1y + c1 = 0 and
a2x + b2y + c2 = 0
a1 = a , b1 = 2 , c1 = -7 ,
a2 = 2 , b2 = 3 , c3 = -8,
a1/a2 ≠ b1/b2
[ Given unique solution ]
=> a/2 ≠ 2/3
=> a ≠ 4/3
•••••
Similar questions