If one of the roots of kx²–7x+3=0 is 3, then k = ......,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) -2
(b) 3
(c) -2
(d) 2
Answers
Answered by
4
(d)2 is the correct answer.
Answered by
12
Option ( d ) is correct.
Explanation :
Given
Quadratic equation kx²-7x+3=0
and 3 is one root of above equation.
Therefore ,
put x = 3 in the equation , we get
k × ( 3² ) - 7( 3 ) + 3 = 0
=> 9k - 21 + 3 = 0
=> 9k - 18 = 0
=> 9k = 18
=> k = 18/9
=> k = 2
•••••
Explanation :
Given
Quadratic equation kx²-7x+3=0
and 3 is one root of above equation.
Therefore ,
put x = 3 in the equation , we get
k × ( 3² ) - 7( 3 ) + 3 = 0
=> 9k - 21 + 3 = 0
=> 9k - 18 = 0
=> 9k = 18
=> k = 18/9
=> k = 2
•••••
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