If one of the roots of the equation kx^2 + 2x – 3 = 0 is 2, then find k.
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Answer:
kx^2+2x-3=0
and it's one root is 2
so it satisfies in this eq.
so we put x=2 in eq.
k(2)^2+2(2)-3=0
k*4+4-3=0
4k=-1
k=-1/4
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