Question

If one of the the zeros of the quadratic polynomial (k-1)x²+kx +1 is -3 find the value of k

Answer 1

Answer:

(k-1)x^2+Kx+1=0

(k-1)(-3)^2+k(-3)+1=0

9k-9-3k+1=0

6k-8=0

6k=8

k=4/3

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Answer 2

Answer:

The answer is 4/3

Explanation:

( k - 1 )x^2 + kx + 1 = 0

Let x be 3

( k - 1 ) ( 3^2) + k(3) + 1 = 0

( k - 1 ) 9 - 3k + 1 = 0

9k - 9 - 3k + 1 = 0

6k - 8 = 0

6k = 8

k = 8/6

k = 4/3