Question

if one of the zero of polynomial (a2 + 9)x2 +13x +6a os reciprocal of the other , find the value of a​

Answer 1

HOLA

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Given , (a^2 + 9)x^2 + 13x + 6a

$\alpha \ \beta \: = \: \frac{ C}{a} \\ \\ \frac{a {}^{2} \: + \: 9 }{6a} \: = > \: a \: = \: \sqrt{9} \: =3 \\ \\ a \: = \frac{6}{3} \: = \: 2$

So value of A is 2

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HOPE U UNDERSTAND ❤❤❤

Answer 2

Step-by-step explanation:

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