If one of the zero of the quadratic polynomial bracket - 1 bracket x ki power 2 + kx + 1 is -3 then find the value of k
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Answered by
0
x²+kx+1
if x=-3
then,(-3)²+k(-3)+1=0
9-3k+1=0
10-3k=0
10=3k
k=10/3
if x=-3
then,(-3)²+k(-3)+1=0
9-3k+1=0
10-3k=0
10=3k
k=10/3
Answered by
2
Step-by-step explanation:
GIVEN:-)
→ One zeros of quadratic polynomial = -3.
→ Quadratic polynomial = ( k - 1 )x² + kx + 1.
Solution:-
→ P(x) = ( k -1 )x² + kx + 1 = 0.
→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.
=> ( k - 1 ) × 9 -3k + 1 = 0.
=> 9k - 9 -3k + 1 = 0.
=> 6k - 8 = 0.
=> 6k = 8.
Hence, the value of ‘k’ is founded .
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