Question

if one of the zero of the quadratic polynomial ( K - 1 ) X square + 3 X + 1 is _3 then find the value of k

Answer 1

If one of the zero of the quadratic polynomial ( K - 1 ) X square + 3 X + 1 is _3 
x=-3
(k-1)(-3)^2  + 3(-3)+1 =0
(k-1)9 -9+1 =0
9k-9-9+1 =0
9k =17
k=17/9

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:- -------------

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8.

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .