Question

if one of the zeroes of cubic polynomial is x3+ax2+bx+is-1 then product of other two zeroes is​

Answer 1

Answer:

1

Step-by-step explanation:

Given cubic polynomial is x^3+ax^2+bx+1

the given zero of the polynomial is -1

the product of the zeroes of the cubic polynomial ax^3+bx^2+cx+d is

‘-d/a’

now compare the coefficients of the general polynomial and the given polynomial we get,

a=1,b=a,c=b,d=1

now,

       The product of the zeroes of the given polynomial is-(d/a)=-(1/1)=-1

but it is given that one of the zero is-1 and let the other two zeroes be

α and β

Now,

        (-1)(α)(β)=-1=>αβ=1

therefore the product of other two zeroes is (αβ)=1

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