Question

if one of the zeroes of (P -1) x^2 + px + 1 is -3 find the value of p​

Answer 1

Answer:

Just plug x=-3 into the polynomial and set it equals to zero cause x=-3 will satisfy the expression, so

(P-1)*(-3)^2 -3P +1=0

9P-9 -3P+1=0=0

6P=8

P=8/6

P=4/3