if one of the zeroes of p(x) =(a^2+4)x^2+13x+4a is a reciprocal of other , then find valie of a
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if one root is reciprocal of other that means there product is 1
product of root = c/a = 1
4a/(a^2+4) =1
4a = a^2 + 4
a^2 + 4 - 4a =0
(a-2)^2 =0
a = 2
hope it helps.
product of root = c/a = 1
4a/(a^2+4) =1
4a = a^2 + 4
a^2 + 4 - 4a =0
(a-2)^2 =0
a = 2
hope it helps.
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