Question

If one of the zeroes of quadratic polynomial x 2
+ kx – 12 is –3, find the other zero &
the value of k.

Answer 1

Answer:

k=-1,    other zero =4

Step-by-step explanation:

p(x)=x^2+kx-12

given,

p(-3)=0

when x=-3 p(x)=0

p(-3)=9-3k-12=0

-3k-3=0

k=-1

other zero be y

-3*y=-12 [alpha*beta=c/a]

y=other zero=4

Answer 2

Step-by-step explanation:

hope my attachment helps u :)

happy learning