Question

If one of the zeroes of the cubic polynomial X3 +ax2+c is -1, thenthe product of the other two Zeroes is

a) b-a+1
b) b-a-1
c) a-b+1
d) a-b-1​

Answer 1

Answer:

Step-by-step explanation:

Given one of zeroes of cubic polynomial=-1

So -1 must satisfy given equation

(-1)^3+a(-1)^2+b(-1)+c=0

-1+a-b+c=0

a-b+c=0   So c= b-a

We know sum of roots=-b/a= -a

Let other two roots be X,Y

X+Y-1=-a

X+Y=1-a

Product of roots taken two at a time= c/a

(-1)(X)+(X)(Y)+(Y)(-1)=b

-X-Y+XY=b

XY=b+X+Y

XY=b+1-a

XY=b-a+1

Please mark as brainliest and thank if it helps..