Question

If one of the zeroes of the quadratic polynomial 2x2 + kx-12 is -4, find the value of k.​

Answer 1

Answer:

k=5

Step-by-step explanation:

x=-4

$2x^{2}+kx-12$

$2(-4)^{2}+k(-4) -12 =0\\32-4k -12=0\\20-4k=0\\-4k=0-20\\ -4k=-20\\k=\frac{-20}{-4}\\k=5$